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Simplify. Assume nn is greater than or equal to zero.\newline75n7\sqrt{75n^7}

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Q. Simplify. Assume nn is greater than or equal to zero.\newline75n7\sqrt{75n^7}
  1. Factorization and Pairing: Factor 75n775n^7 into its prime factors and pair the factors to form perfect squares where possible.\newline7575 can be factored into 3×5×53 \times 5 \times 5, and n7n^7 can be written as n6×nn^6 \times n, where n6n^6 is a perfect square since it has an even exponent.\newlineSo, we have 75n7=3×52×n6×n\sqrt{75n^7} = \sqrt{3 \times 5^2 \times n^6 \times n}.
  2. Separation of Squares: Separate the perfect squares from the non-perfect squares inside the square root. We can rewrite the expression as 52×n6×3n\sqrt{5^2 \times n^6} \times \sqrt{3n}.
  3. Simplification: Simplify the square root of the perfect squares.\newlineSince 52\sqrt{5^2} is 55 and n6\sqrt{n^6} is n3n^3 (because the square root of n6n^6 is the number nn raised to the power of 62\frac{6}{2}, which is 33), we get:\newline5×n3×3n5 \times n^3 \times \sqrt{3n}.
  4. Final Expression: Write the final simplified expression.\newlineThe final simplified expression is 5n33n5n^3 \cdot \sqrt{3n}.

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