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Simplify. Assume all variables are positive.\newlinex23x53x13\frac{x^{\frac{2}{3}}}{x^{\frac{5}{3}} \cdot x^{\frac{1}{3}}}\newlineWrite your answer in the form AA or AB\frac{A}{B}, where AA and BB are constants or variable expressions that have no variables in common. All exponents in your answer should be positive.\newline______

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Q. Simplify. Assume all variables are positive.\newlinex23x53x13\frac{x^{\frac{2}{3}}}{x^{\frac{5}{3}} \cdot x^{\frac{1}{3}}}\newlineWrite your answer in the form AA or AB\frac{A}{B}, where AA and BB are constants or variable expressions that have no variables in common. All exponents in your answer should be positive.\newline______
  1. Combine Exponents: Combine the exponents in the denominator using the property of exponents that states when you multiply like bases, you add the exponents.\newlinex53×x13=x53+13x^{\frac{5}{3}} \times x^{\frac{1}{3}} = x^{\frac{5}{3} + \frac{1}{3}}
  2. Add Exponents: Add the exponents in the denominator.\newline53+13=63\frac{5}{3} + \frac{1}{3} = \frac{6}{3}\newlinex53+13=x63x^{\frac{5}{3} + \frac{1}{3}} = x^{\frac{6}{3}}
  3. Simplify Exponent: Simplify the exponent in the denominator. \newline63=2\frac{6}{3} = 2\newlinex63=x2x^{\frac{6}{3}} = x^2
  4. Rewrite Expression: Rewrite the original expression with the simplified denominator. \newlinex23/(x53x13)=x23/x2x^{\frac{2}{3}} / (x^{\frac{5}{3}} \cdot x^{\frac{1}{3}}) = x^{\frac{2}{3}} / x^2
  5. Apply Property: Apply the property of exponents that states when you divide like bases, you subtract the exponents.\newlinex23/x2=x232x^{\frac{2}{3}} / x^2 = x^{\frac{2}{3} - 2}
  6. Convert Exponent: Convert the whole number exponent to a fraction to subtract the exponents.\newline2=632 = \frac{6}{3}\newlinex232=x2363x^{\frac{2}{3} - 2} = x^{\frac{2}{3} - \frac{6}{3}}
  7. Subtract Exponents: Subtract the exponents.\newline2363=43\frac{2}{3} - \frac{6}{3} = -\frac{4}{3}\newlinex(2363)=x43x^{\left(\frac{2}{3} - \frac{6}{3}\right)} = x^{-\frac{4}{3}}
  8. Rewrite Exponent: Since we want all exponents to be positive, we can rewrite x(4/3)x^{(-4/3)} as 1/x(4/3)1/x^{(4/3)}.\newlinex(4/3)=1/x(4/3)x^{(-4/3)} = 1/x^{(4/3)}

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