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Simplify. Assume all variables are positive.\newlineb83b43b23\frac{b^{\frac{8}{3}}}{b^{\frac{4}{3}} \cdot b^{\frac{2}{3}}}\newlineWrite your answer in the form AA or AB\frac{A}{B}, where AA and BB are constants or variable expressions that have no variables in common. All exponents in your answer should be positive.\newline______

Full solution

Q. Simplify. Assume all variables are positive.\newlineb83b43b23\frac{b^{\frac{8}{3}}}{b^{\frac{4}{3}} \cdot b^{\frac{2}{3}}}\newlineWrite your answer in the form AA or AB\frac{A}{B}, where AA and BB are constants or variable expressions that have no variables in common. All exponents in your answer should be positive.\newline______
  1. Simplify Denominator: We have the expression: b83/(b43b23)b^{\frac{8}{3}} / (b^{\frac{4}{3}} * b^{\frac{2}{3}})\newlineFirst, let's simplify the denominator using the property of exponents that states aman=am+na^{m} * a^{n} = a^{m+n}.\newlineb43b23=b43+23b^{\frac{4}{3}} * b^{\frac{2}{3}} = b^{\frac{4}{3} + \frac{2}{3}}
  2. Add Exponents: Now, let's add the exponents in the denominator.\newline43+23=63\frac{4}{3} + \frac{2}{3} = \frac{6}{3}\newlineSo, b43×b23=b63b^{\frac{4}{3}} \times b^{\frac{2}{3}} = b^{\frac{6}{3}}
  3. Rewrite Denominator: Since 63\frac{6}{3} simplifies to 22, we can rewrite the denominator as b2b^2. \newlineb63=b2b^{\frac{6}{3}} = b^2\newlineNow, our expression is b83b2\frac{b^{\frac{8}{3}}}{b^2}
  4. Apply Exponent Property: Next, we apply the property of exponents that states am/an=amna^{m} / a^{n} = a^{m-n} to simplify the expression.\newlineb83/b2=b832b^{\frac{8}{3}} / b^{2} = b^{\frac{8}{3} - 2}
  5. Subtract Exponents: We need to express 22 as a fraction with a denominator of 33 to subtract it from 83\frac{8}{3}. 22 can be written as 63\frac{6}{3}, so the expression becomes b(8363)b^{\left(\frac{8}{3} - \frac{6}{3}\right)}.
  6. Final Answer: Now, let's subtract the exponents.\newline8363=23\frac{8}{3} - \frac{6}{3} = \frac{2}{3}\newlineSo, b83/b2=b23b^{\frac{8}{3}} / b^2 = b^{\frac{2}{3}}
  7. Final Answer: Now, let's subtract the exponents.\newline8363=23\frac{8}{3} - \frac{6}{3} = \frac{2}{3}\newlineSo, b83/b2=b23b^{\frac{8}{3}} / b^2 = b^{\frac{2}{3}}The expression is now fully simplified, and there are no negative exponents.\newlineThe final answer is b23b^{\frac{2}{3}}.

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