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Select the outlier in the data set.\newline8,46,52,55,57,60,62,728, 46, 52, 55, 57, 60, 62, 72\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Identify an outlier and describe the effect of removing itright chevron icon

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Q. Select the outlier in the data set.\newline8,46,52,55,57,60,62,728, 46, 52, 55, 57, 60, 62, 72\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the given data set.\newlineThe data set is: 8,46,52,55,57,60,62,728, 46, 52, 55, 57, 60, 62, 72.\newlineAn outlier is a data point that is significantly different from the rest of the data. We can often spot an outlier by looking for a number that is much smaller or larger than the rest.\newlineIn this case, the number 88 stands out as being much smaller than the other numbers in the set.
  2. Calculate Mean with Outlier: Calculate the mean of the data set with the outlier included.\newlineTo find the mean, add all the numbers together and divide by the number of data points.\newlineMean = (8+46+52+55+57+60+62+72)/8(8 + 46 + 52 + 55 + 57 + 60 + 62 + 72) / 8\newlineMean = (362)/8(362) / 8\newlineMean = 45.2545.25
  3. Remove Outlier, Recalculate Mean: Remove the outlier and calculate the new mean of the data set.\newlineThe new data set without the outlier 88 is: 46,52,55,57,60,62,7246, 52, 55, 57, 60, 62, 72.\newlineNow, add these numbers together and divide by the new number of data points, which is 77.\newlineNew Mean = (46+52+55+57+60+62+72)/7(46 + 52 + 55 + 57 + 60 + 62 + 72) / 7\newlineNew Mean = (404)/7(404) / 7\newlineNew Mean = 57.7157.71 (rounded to two decimal places)
  4. Compare Means: Compare the two means to determine if the mean increased or decreased after removing the outlier. The original mean was 45.2545.25, and the new mean without the outlier is 57.7157.71. Since 57.7157.71 is greater than 45.2545.25, the mean increased after removing the outlier.

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