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Select the outlier in the data set.\newline79,85,87,88,89,90,92,74779, 85, 87, 88, 89, 90, 92, 747\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline79,85,87,88,89,90,92,74779, 85, 87, 88, 89, 90, 92, 747\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the given data set.\newlineThe data set is: 7979, 8585, 8787, 8888, 8989, 9090, 9292, 747747.\newlineAn outlier is a value that is significantly higher or lower than the rest of the data. In this case, 747747 is much higher than all other values, so it is the outlier.
  2. Calculate Mean with Outlier: Calculate the mean of the data set with the outlier included.\newlineTo find the mean, add all the numbers together and divide by the number of values.\newlineMean = (79+85+87+88+89+90+92+747)/8(79 + 85 + 87 + 88 + 89 + 90 + 92 + 747) / 8\newlineMean = (1257+747)/8(1257 + 747) / 8\newlineMean = 2004/82004 / 8\newlineMean = 250.5250.5
  3. Calculate Mean without Outlier: Calculate the mean of the data set without the outlier. Remove the outlier 747747 and calculate the new mean. New Mean = (79+85+87+88+89+90+92)/7(79 + 85 + 87 + 88 + 89 + 90 + 92) / 7 New Mean = (610)/7(610) / 7 New Mean = 87.1487.14 (rounded to two decimal places)
  4. Compare Mean Changes: Compare the means to determine if the mean increases or decreases after removing the outlier. The original mean with the outlier was 250.5250.5, and the new mean without the outlier is 87.1487.14. Since 87.1487.14 is less than 250.5250.5, the mean decreases when the outlier is removed.

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