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Select the outlier in the data set.\newline7,84,88,90,91,93,95,97,987, 84, 88, 90, 91, 93, 95, 97, 98\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline7,84,88,90,91,93,95,97,987, 84, 88, 90, 91, 93, 95, 97, 98\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the data set.\newlineTo find the outlier, we can look for a number that is significantly different from the rest of the numbers in the set. In this case, the number 77 stands out as it is much lower than all other numbers, which are all above 8080.
  2. Calculate Mean: Calculate the mean of the original data set.\newlineTo calculate the mean, add all the numbers together and divide by the number of values in the set.\newlineMean = (7+84+88+90+91+93+95+97+98)/9(7 + 84 + 88 + 90 + 91 + 93 + 95 + 97 + 98) / 9\newlineMean = (743)/9(743) / 9\newlineMean ≈82.56\approx 82.56
  3. Remove Outlier: Remove the outlier and calculate the new mean.\newlineWithout the number 77, the new data set is:\newline84,88,90,91,93,95,97,9884, 88, 90, 91, 93, 95, 97, 98\newlineNow calculate the new mean:\newlineNew Mean = (84+88+90+91+93+95+97+98)/8(84 + 88 + 90 + 91 + 93 + 95 + 97 + 98) / 8\newlineNew Mean = (736)/8(736) / 8\newlineNew Mean = 9292
  4. Compare Means: Compare the original mean to the new mean to determine if it would increase or decrease. The original mean was approximately 82.5682.56, and the new mean is 9292. Since 9292 is greater than 82.5682.56, removing the outlier (7)(7) has increased the mean.

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