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Select the outlier in the data set.\newline66,76,82,84,85,86,95,99,38266, 76, 82, 84, 85, 86, 95, 99, 382\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Identify an outlier and describe the effect of removing itright chevron icon

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Q. Select the outlier in the data set.\newline66,76,82,84,85,86,95,99,38266, 76, 82, 84, 85, 86, 95, 99, 382\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the given data set: 66,76,82,84,85,86,95,99,38266, 76, 82, 84, 85, 86, 95, 99, 382. An outlier is a data point that is significantly different from the rest of the data. In this case, 382382 stands out as it is much higher than the other values.
  2. Calculate Mean with Outlier: Calculate the mean of the data set with the outlier included:\newlineMean = (66+76+82+84+85+86+95+99+382)/9(66 + 76 + 82 + 84 + 85 + 86 + 95 + 99 + 382) / 9\newlineMean = 1055/91055 / 9\newlineMean ≈117.22\approx 117.22
  3. Calculate Mean without Outlier: Calculate the mean of the data set without the outlier:\newlineMean = 66+76+82+84+85+86+95+998\frac{66 + 76 + 82 + 84 + 85 + 86 + 95 + 99}{8}\newlineMean = 6738\frac{673}{8}\newlineMean ≈84.13\approx 84.13
  4. Compare Means: Compare the means to determine if the mean would increase or decrease upon the removal of the outlier: The mean without the outlier (84.1384.13) is less than the mean with the outlier (117.22117.22). Therefore, removing the outlier would decrease the mean.

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