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Select the outlier in the data set.\newline64,71,73,75,76,77,79,86164, 71, 73, 75, 76, 77, 79, 861\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline64,71,73,75,76,77,79,86164, 71, 73, 75, 76, 77, 79, 861\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the data set.\newlineTo find the outlier, we look for a number that is significantly different from the rest of the numbers in the set. In this case, the number 861861 stands out as it is much larger than the other numbers.
  2. Calculate Mean with Outlier: Calculate the mean of the data set including the outlier.\newlineTo calculate the mean, we add all the numbers together and then divide by the number of values in the set.\newlineMean = (64+71+73+75+76+77+79+861)/8(64 + 71 + 73 + 75 + 76 + 77 + 79 + 861) / 8\newlineMean = (1376+861)/8(1376 + 861) / 8\newlineMean = 2237/82237 / 8\newlineMean = 279.625279.625
  3. Calculate Mean without Outlier: Calculate the mean of the data set without the outlier.\newlineWe remove the outlier 861861 and then calculate the mean of the remaining numbers.\newlineMean without outlier = (64+71+73+75+76+77+79)/7(64 + 71 + 73 + 75 + 76 + 77 + 79) / 7\newlineMean without outlier = 515/7515 / 7\newlineMean without outlier = 73.571473.5714 (approximately)
  4. Compare Mean Changes: Compare the two means to determine if the mean would increase or decrease upon removal of the outlier. The mean with the outlier is 279.625279.625, and the mean without the outlier is approximately 73.571473.5714. Since the mean without the outlier is lower, removing the outlier would decrease the mean.

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