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Select the outlier in the data set.\newline64,69,71,72,73,74,76,15664, 69, 71, 72, 73, 74, 76, 156\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline64,69,71,72,73,74,76,15664, 69, 71, 72, 73, 74, 76, 156\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the given data set: 64,69,71,72,73,74,76,15664, 69, 71, 72, 73, 74, 76, 156. An outlier is a data point that is significantly different from the rest of the data. We can visually inspect the data set and see that 156156 is much larger than all other numbers, which are relatively close to each other.
  2. Confirm Outlier: To confirm that 156156 is an outlier, we can calculate the interquartile range (IQR) and then determine the upper bound above which a data point would be considered an outlier. However, since 156156 is clearly much larger than the rest, we can proceed without this calculation.
  3. Calculate Mean with Outlier: Calculate the mean of the data set with the outlier included: (64+69+71+72+73+74+76+156)/8(64 + 69 + 71 + 72 + 73 + 74 + 76 + 156) / 8. Perform the calculation: 645/8=80.625645 / 8 = 80.625.
  4. Calculate Mean without Outlier: Calculate the mean of the data set without the outlier: (64+69+71+72+73+74+76)/7(64 + 69 + 71 + 72 + 73 + 74 + 76) / 7. Perform the calculation: 499/7=71.2857499 / 7 = 71.2857.
  5. Compare Means: Compare the two means: with the outlier, the mean is 80.62580.625; without the outlier, the mean is 71.285771.2857. Since the mean without the outlier is less than the mean with the outlier, removing the outlier would decrease the mean.

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