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Select the outlier in the data set.\newline6,62,64,70,75,76,82,926, 62, 64, 70, 75, 76, 82, 92\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline6,62,64,70,75,76,82,926, 62, 64, 70, 75, 76, 82, 92\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Step 11: Identify the outlier in the data set.\newlineData set: 6,62,64,70,75,76,82,926, 62, 64, 70, 75, 76, 82, 92\newlineTo find the outlier, look for a number that is significantly different from the rest.\newlineOutlier: 66 (significantly lower than the other numbers)
  2. Calculate Mean: Step 22: Calculate the mean of the original data set.\newlineMean = (6+62+64+70+75+76+82+92)/8(6 + 62 + 64 + 70 + 75 + 76 + 82 + 92) / 8\newlineMean = 527/8527 / 8\newlineMean = 65.87565.875
  3. Calculate New Mean: Step 33: Calculate the mean of the data set without the outlier.\newlineNew data set without outlier: 62,64,70,75,76,82,9262, 64, 70, 75, 76, 82, 92\newlineMean = (62+64+70+75+76+82+92)/7(62 + 64 + 70 + 75 + 76 + 82 + 92) / 7\newlineMean = 521/7521 / 7\newlineMean = 74.428674.4286
  4. Compare Means: Step 44: Compare the two means to determine if the mean increases or decreases.\newlineOriginal mean: 65.87565.875\newlineNew mean without outlier: 74.428674.4286\newlineSince 74.428674.4286 is greater than 65.87565.875, removing the outlier increases the mean.

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