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Select the outlier in the data set.\newline5,78,88,89,90,93,94,96,985, 78, 88, 89, 90, 93, 94, 96, 98\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline5,78,88,89,90,93,94,96,985, 78, 88, 89, 90, 93, 94, 96, 98\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Step 11: Identify the outlier in the data set.\newlineData set: 5,78,88,89,90,93,94,96,985, 78, 88, 89, 90, 93, 94, 96, 98\newlineOutlier is typically a number that is significantly different from the rest of the data. Here, 55 is much lower than all other numbers.
  2. Calculate Mean: Step 22: Calculate the mean of the original data set.\newlineMean = (5+78+88+89+90+93+94+96+98)/9(5 + 78 + 88 + 89 + 90 + 93 + 94 + 96 + 98) / 9\newlineMean = 731/9731 / 9\newlineMean = 81.2281.22
  3. Remove Outlier: Step 33: Remove the outlier and calculate the new mean.\newlineNew data set without outlier: 78,88,89,90,93,94,96,9878, 88, 89, 90, 93, 94, 96, 98\newlineNew mean = (78+88+89+90+93+94+96+98)/8(78 + 88 + 89 + 90 + 93 + 94 + 96 + 98) / 8\newlineNew mean = 726/8726 / 8\newlineNew mean = 90.7590.75
  4. Compare Means: Step 44: Compare the original mean and the new mean to determine if the mean increased or decreased.\newlineOriginal mean = 81.2281.22, New mean = 90.7590.75\newlineSince 90.7590.75 is greater than 81.2281.22, the mean increased after removing the outlier.

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