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Select the outlier in the data set.\newline5,66,72,73,77,80,90,975, 66, 72, 73, 77, 80, 90, 97\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline5,66,72,73,77,80,90,975, 66, 72, 73, 77, 80, 90, 97\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Step 11: Identify the outlier in the data set.\newlineData set: 5,66,72,73,77,80,90,975, 66, 72, 73, 77, 80, 90, 97.\newlineTo find the outlier, look for a number that is significantly different from the rest. Here, 55 is much lower than all other numbers.
  2. Calculate Mean: Step 22: Calculate the mean of the original data set.\newlineMean = (5+66+72+73+77+80+90+97)/8(5 + 66 + 72 + 73 + 77 + 80 + 90 + 97) / 8\newlineMean = 560/8=70560 / 8 = 70
  3. Calculate Mean Without Outlier: Step 33: Calculate the mean without the outlier 55. New data set: 66,72,73,77,80,90,9766, 72, 73, 77, 80, 90, 97. Mean = (66+72+73+77+80+90+97)/7(66 + 72 + 73 + 77 + 80 + 90 + 97) / 7 Mean = 555/7=79.29555 / 7 = 79.29
  4. Compare Means: Step 44: Compare the two means to determine if the mean increases or decreases after removing the outlier. Original mean = 7070, New mean without outlier = 79.2979.29. Since 79.2979.29 is greater than 7070, the mean increases after removing the outlier.

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