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Select the outlier in the data set.\newline5,64,66,72,73,77,79,81,915, 64, 66, 72, 73, 77, 79, 81, 91\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline5,64,66,72,73,77,79,81,915, 64, 66, 72, 73, 77, 79, 81, 91\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Step 11: Identify the outlier in the data set.\newlineData set: 5,64,66,72,73,77,79,81,915, 64, 66, 72, 73, 77, 79, 81, 91.\newlineOutliers are numbers that are significantly different from the others. Here, 55 is much lower than all other numbers.
  2. Calculate Mean: Step 22: Calculate the mean of the original data set.\newlineMean = (5+64+66+72+73+77+79+81+91)/9(5 + 64 + 66 + 72 + 73 + 77 + 79 + 81 + 91) / 9\newlineMean = 608/9608 / 9\newlineMean = 67.5667.56
  3. Remove Outlier & Recalculate Mean: Step 33: Remove the outlier 55 and calculate the new mean.\newlineNew data set: 64,66,72,73,77,79,81,9164, 66, 72, 73, 77, 79, 81, 91.\newlineNew mean =(64+66+72+73+77+79+81+91)/8= (64 + 66 + 72 + 73 + 77 + 79 + 81 + 91) / 8\newlineNew mean =603/8= 603 / 8\newlineNew mean =75.375= 75.375
  4. Compare Original and New Mean: Step 44: Compare the original mean and the new mean.\newlineOriginal mean: 67.5667.56\newlineNew mean: 75.37575.375\newlineSince the new mean (75.37575.375) is greater than the original mean (67.5667.56), removing the outlier 55 causes the mean to increase.

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