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Select the outlier in the data set.\newline4,73,79,82,86,89,91,97,984, 73, 79, 82, 86, 89, 91, 97, 98\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline4,73,79,82,86,89,91,97,984, 73, 79, 82, 86, 89, 91, 97, 98\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the data set.\newlineTo find the outlier, we can look for a number that is significantly different from the rest of the numbers in the set. In this case, the number 44 stands out as it is much lower than all other numbers which are all above 7070.
  2. Calculate Mean with Outlier: Calculate the mean of the data set including the outlier.\newlineTo calculate the mean, add all the numbers together and divide by the number of values in the set.\newlineMean = (4+73+79+82+86+89+91+97+98)/9(4 + 73 + 79 + 82 + 86 + 89 + 91 + 97 + 98) / 9\newlineMean = (699)/9(699) / 9\newlineMean = 77.6777.67 (rounded to two decimal places)
  3. Calculate Mean without Outlier: Calculate the mean of the data set without the outlier.\newlineRemove the outlier 44 and calculate the new mean.\newlineNew Mean = (73+79+82+86+89+91+97+98)/8(73 + 79 + 82 + 86 + 89 + 91 + 97 + 98) / 8\newlineNew Mean = (695)/8(695) / 8\newlineNew Mean = 86.87586.875
  4. Compare Mean Changes: Compare the two means to determine if the mean would increase or decrease upon removal of the outlier. The original mean was 77.6777.67, and the new mean without the outlier is 86.87586.875. Since the new mean is higher, the mean would increase if the outlier were removed.

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