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Select the outlier in the data set.\newline3,65,69,73,78,80,84,903, 65, 69, 73, 78, 80, 84, 90\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Identify an outlier and describe the effect of removing itright chevron icon

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Q. Select the outlier in the data set.\newline3,65,69,73,78,80,84,903, 65, 69, 73, 78, 80, 84, 90\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the given data set: 3,65,69,73,78,80,84,903, 65, 69, 73, 78, 80, 84, 90. To find the outlier, we can look for a number that is significantly different from the rest of the data. In this case, 33 is much lower than all other numbers, which are all above 6060.
  2. Calculate Mean with Outlier: Calculate the mean of the data set with the outlier included: (3+65+69+73+78+80+84+90)/8(3 + 65 + 69 + 73 + 78 + 80 + 84 + 90) / 8. Perform the addition: 3+65+69+73+78+80+84+90=5423 + 65 + 69 + 73 + 78 + 80 + 84 + 90 = 542. Now divide by the number of data points: 542/8=67.75542 / 8 = 67.75. The mean with the outlier is 67.7567.75.
  3. Calculate Mean without Outlier: Calculate the mean of the data set without the outlier: (65+69+73+78+80+84+90)/7(65 + 69 + 73 + 78 + 80 + 84 + 90) / 7. Perform the addition: 65+69+73+78+80+84+90=53965 + 69 + 73 + 78 + 80 + 84 + 90 = 539. Now divide by the number of data points: 539/7≈77539 / 7 \approx 77. The mean without the outlier is approximately 7777.
  4. Compare Mean with and without Outlier: Compare the two means to determine if the mean would increase or decrease upon the removal of the outlier.\newlineThe mean with the outlier is 67.7567.75, and the mean without the outlier is approximately 7777.\newlineSince 7777 is greater than 67.7567.75, the mean would increase if the outlier were removed.

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