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Select the outlier in the data set.\newline2,59,63,65,66,67,69,702, 59, 63, 65, 66, 67, 69, 70\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Identify an outlier and describe the effect of removing itright chevron icon

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Q. Select the outlier in the data set.\newline2,59,63,65,66,67,69,702, 59, 63, 65, 66, 67, 69, 70\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the given data set.\newlineThe data set is: 2,59,63,65,66,67,69,702, 59, 63, 65, 66, 67, 69, 70.\newlineAn outlier is a data point that is significantly different from the rest of the data. In this case, the number 22 stands out as being much lower than all other numbers.
  2. Calculate Mean: Calculate the mean of the data set including the outlier.\newlineTo find the mean, add all the numbers together and divide by the number of data points.\newlineMean = (2+59+63+65+66+67+69+70)/8(2 + 59 + 63 + 65 + 66 + 67 + 69 + 70) / 8\newlineMean = (461)/8(461) / 8\newlineMean = 57.62557.625
  3. Remove Outlier: Remove the outlier and calculate the new mean of the data set.\newlineWithout the number 22, the data set is: 59,63,65,66,67,69,7059, 63, 65, 66, 67, 69, 70.\newlineMean without outlier = (59+63+65+66+67+69+70)/7(59 + 63 + 65 + 66 + 67 + 69 + 70) / 7\newlineMean without outlier = (459)/7(459) / 7\newlineMean without outlier = 65.5714285714285765.57142857142857
  4. Compare Means: Compare the means to determine if the mean increases or decreases after removing the outlier. The original mean with the outlier was 57.62557.625, and the mean without the outlier is approximately 65.5765.57. Since 65.5765.57 is greater than 57.62557.625, removing the outlier increases the mean.

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