Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Select the outlier in the data set.\newline14,23,33,50,69,74,77,79,98614, 23, 33, 50, 69, 74, 77, 79, 986\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

Full solution

Q. Select the outlier in the data set.\newline14,23,33,50,69,74,77,79,98614, 23, 33, 50, 69, 74, 77, 79, 986\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the data set.\newlineTo find the outlier, we look for a number that is significantly different from the rest of the numbers in the data set. In this case, 986986 stands out as it is much larger than the other numbers.
  2. Calculate Mean with Outlier: Calculate the mean of the data set including the outlier.\newlineTo calculate the mean, we add all the numbers together and then divide by the number of values in the data set.\newlineMean = (14+23+33+50+69+74+77+79+986)/9(14 + 23 + 33 + 50 + 69 + 74 + 77 + 79 + 986) / 9\newlineMean = (1405)/9(1405) / 9\newlineMean 156.11\approx 156.11
  3. Calculate Mean without Outlier: Calculate the mean of the data set without the outlier.\newlineTo calculate the new mean, we remove the outlier 986986 and then add the remaining numbers together and divide by the new number of values in the data set.\newlineNew Mean = (14+23+33+50+69+74+77+79)/8(14 + 23 + 33 + 50 + 69 + 74 + 77 + 79) / 8\newlineNew Mean = (419)/8(419) / 8\newlineNew Mean 52.375\approx 52.375
  4. Compare Means: Compare the two means to determine if the mean would increase or decrease upon removal of the outlier. The original mean with the outlier was approximately 156.11156.11, and the new mean without the outlier is approximately 52.37552.375. Since the new mean is lower than the original mean, the mean would decrease if the outlier were removed.

More problems from Identify an outlier and describe the effect of removing it