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Select the outlier in the data set.\newline12,22,46,47,67,79,85,40012, 22, 46, 47, 67, 79, 85, 400\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline12,22,46,47,67,79,85,40012, 22, 46, 47, 67, 79, 85, 400\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify the outlier: Identify the outlier in the data set.\newlineTo find the outlier, we look for a number that is significantly different from the rest of the numbers in the set. In this case, 400400 is much larger than all other numbers, which range from 1212 to 8585. Therefore, 400400 is the outlier.
  2. Calculate mean with outlier: Calculate the mean of the data set with the outlier.\newlineTo find the mean, we add all the numbers together and divide by the total count of numbers. The sum of the data set including the outlier is 12+22+46+47+67+79+85+400=75812 + 22 + 46 + 47 + 67 + 79 + 85 + 400 = 758. The total count of numbers is 88. So, the mean is 758/8=94.75758 / 8 = 94.75.
  3. Calculate mean without outlier: Calculate the mean of the data set without the outlier.\newlineTo find the new mean, we subtract the outlier from the sum calculated in Step 22 and then divide by the new total count of numbers. The new sum is 758400=358758 - 400 = 358. The new total count of numbers is 81=78 - 1 = 7. So, the new mean is 358/751.14358 / 7 \approx 51.14.
  4. Determine mean change: Determine if the mean will increase or decrease after removing the outlier. Comparing the original mean 94.7594.75 with the new mean 51.1451.14, we can see that the mean decreases when the outlier is removed.

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