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Select the outlier in the data set.\newline12,22,36,50,51,53,58,62,84912, 22, 36, 50, 51, 53, 58, 62, 849\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline12,22,36,50,51,53,58,62,84912, 22, 36, 50, 51, 53, 58, 62, 849\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Step 11: Identify the outlier in the data set.\newlineData set: 12,22,36,50,51,53,58,62,84912, 22, 36, 50, 51, 53, 58, 62, 849\newlineOutliers are values that are much higher or lower than the rest of the data. 849849 stands out as it is significantly higher than all other values.
  2. Calculate Mean with Outlier: Step 22: Calculate the mean of the data set including the outlier.\newlineMean = (12+22+36+50+51+53+58+62+849)/9(12 + 22 + 36 + 50 + 51 + 53 + 58 + 62 + 849) / 9\newlineMean = 1193/91193 / 9\newlineMean = 132.56132.56
  3. Calculate Mean without Outlier: Step 33: Calculate the mean of the data set without the outlier.\newlineMean without outlier = (12+22+36+50+51+53+58+62)/8(12 + 22 + 36 + 50 + 51 + 53 + 58 + 62) / 8\newlineMean without outlier = 344/8344 / 8\newlineMean without outlier = 4343
  4. Compare Mean Changes: Step 44: Compare the two means to determine if the mean increases or decreases when the outlier is removed.\newlineMean with outlier = 132.56132.56\newlineMean without outlier = 4343\newlineRemoving the outlier decreases the mean.

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