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Select the outlier in the data set.\newline11,12,14,19,20,34,48,27311, 12, 14, 19, 20, 34, 48, 273\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

Full solution

Q. Select the outlier in the data set.\newline11,12,14,19,20,34,48,27311, 12, 14, 19, 20, 34, 48, 273\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the data set.\newlineTo find the outlier, we can look for a number that is significantly different from the rest of the numbers in the set. In the given data set, 273273 stands out as much larger than the other numbers.
  2. Calculate Mean with Outlier: Calculate the mean of the data set including the outlier.\newlineTo calculate the mean, add all the numbers together and divide by the total count of numbers.\newlineMean = (11+12+14+19+20+34+48+273)/8(11 + 12 + 14 + 19 + 20 + 34 + 48 + 273) / 8\newlineMean = 431/8431 / 8\newlineMean = 53.87553.875
  3. Calculate Mean without Outlier: Calculate the mean of the data set without the outlier. Remove the outlier 273273 and calculate the new mean. New Mean = (11+12+14+19+20+34+48)/7(11 + 12 + 14 + 19 + 20 + 34 + 48) / 7 New Mean = 158/7158 / 7 New Mean = 22.571422.5714 (rounded to four decimal places)
  4. Compare Means: Compare the means to determine if the mean would increase or decrease upon removal of the outlier. The original mean with the outlier is 53.87553.875, and the new mean without the outlier is 22.571422.5714. Since the new mean is lower than the original mean, the mean would decrease if the outlier were removed.

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