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Select the outlier in the data set.\newline1,66,68,70,71,79,87,961, 66, 68, 70, 71, 79, 87, 96\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline1,66,68,70,71,79,87,961, 66, 68, 70, 71, 79, 87, 96\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the data set.\newlineTo find the outlier, we can look for a number that is significantly different from the rest of the numbers in the set. In this case, the number 11 stands out as being much lower than all other numbers.
  2. Calculate Mean with Outlier: Calculate the mean of the data set including the outlier.\newlineTo calculate the mean, add all the numbers together and divide by the total count of numbers.\newlineMean = (1+66+68+70+71+79+87+96)/8(1 + 66 + 68 + 70 + 71 + 79 + 87 + 96) / 8\newlineMean = 538/8538 / 8\newlineMean = 67.2567.25
  3. Calculate Mean without Outlier: Calculate the mean of the data set without the outlier.\newlineRemove the outlier (11) and calculate the new mean.\newlineNew Mean = (66+68+70+71+79+87+96)/7(66 + 68 + 70 + 71 + 79 + 87 + 96) / 7\newlineNew Mean = 537/7537 / 7\newlineNew Mean = 76.7176.71
  4. Compare Means: Compare the means to determine if the mean would increase or decrease. The original mean was 67.2567.25, and the new mean without the outlier is 76.7176.71. Since 76.7176.71 is greater than 67.2567.25, the mean would increase if the outlier were removed.

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