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Select the outlier in the data set.\newline1,42,48,52,53,54,56,641, 42, 48, 52, 53, 54, 56, 64\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

Full solution

Q. Select the outlier in the data set.\newline1,42,48,52,53,54,56,641, 42, 48, 52, 53, 54, 56, 64\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the data set.\newlineTo find the outlier, we can look for a number that is significantly different from the rest of the numbers in the set. In this case, the number 11 stands out as being much lower than all other numbers.
  2. Calculate Mean: Calculate the mean of the original data set.\newlineTo calculate the mean, add all the numbers together and divide by the total count of numbers.\newlineMean = (1+42+48+52+53+54+56+64)/8(1 + 42 + 48 + 52 + 53 + 54 + 56 + 64) / 8\newlineMean = (370)/8(370) / 8\newlineMean = 46.2546.25
  3. Remove Outlier: Remove the outlier and calculate the new mean.\newlineWithout the number 11, the new data set is 42,48,52,53,54,56,6442, 48, 52, 53, 54, 56, 64.\newlineNew Mean = (42+48+52+53+54+56+64)/7(42 + 48 + 52 + 53 + 54 + 56 + 64) / 7\newlineNew Mean = (369)/7(369) / 7\newlineNew Mean = 52.7152.71 (rounded to two decimal places)
  4. Compare Means: Compare the original mean to the new mean to determine if it would increase or decrease.\newlineThe original mean was 46.2546.25, and the new mean is 52.7152.71. Since the new mean is higher than the original mean, removing the outlier would cause the mean to increase.

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