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Select Equation Given Set of Points

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Q. Select Equation Given Set of Points
  1. Calculate Slope Differences: To find the equation that corresponds to the given set of points, we need to determine if there is a linear relationship between the xx and yy values. We can start by calculating the differences in yy-values and xx-values between consecutive points to see if the slope is constant.
  2. Calculate Slope: The slope mm between the first two points (1,4)(1, 4) and (2,7)(2, 7) is calculated as y2y1x2x1=7421=31=3\frac{y_2 - y_1}{x_2 - x_1} = \frac{7 - 4}{2 - 1} = \frac{3}{1} = 3.
  3. Determine Linearity: Now, let's calculate the slope between the second and third points (2,7)(2, 7) and (3,10)(3, 10). The slope is (y3y2)/(x3x2)=(107)/(32)=3/1=3(y_3 - y_2) / (x_3 - x_2) = (10 - 7) / (3 - 2) = 3 / 1 = 3.
  4. Find Y-Intercept: Since the slope is the same between the first two points and the second two points, we can conclude that the points lie on a straight line, and the slope of that line is 33.
  5. Solve for Y-Intercept: Next, we need to find the y-intercept bb of the line. We can use any of the given points for this. Let's use the first point (1,4)(1, 4). The equation of a line is y=mx+by = mx + b, where mm is the slope and bb is the y-intercept. Plugging in the values, we get 4=3(1)+b4 = 3(1) + b.
  6. Final Equation: Solving for bb, we get b=43=1b = 4 - 3 = 1.
  7. Final Equation: Solving for bb, we get b=43=1b = 4 - 3 = 1.Now we have both the slope (m=3m = 3) and the y-intercept (b=1b = 1), so the equation of the line is y=3x+1y = 3x + 1.

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