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Sean, an office manager, needs to find a courier to deliver a package. The first courier he is considering charges a fee of $20\$20 plus $1\$1 per pound. The second charges $8\$8 plus $3\$3 per pound.\newlineSean determines that, given his package's weight, the two courier services are equivalent in terms of cost. How much will it cost to deliver the package? How much does Sean's package weigh?\newlineIt will cost $\$____ to deliver Sean's package using either courier service. The package weighs ____ pounds.

Full solution

Q. Sean, an office manager, needs to find a courier to deliver a package. The first courier he is considering charges a fee of $20\$20 plus $1\$1 per pound. The second charges $8\$8 plus $3\$3 per pound.\newlineSean determines that, given his package's weight, the two courier services are equivalent in terms of cost. How much will it cost to deliver the package? How much does Sean's package weigh?\newlineIt will cost $\$____ to deliver Sean's package using either courier service. The package weighs ____ pounds.
  1. Cost Equation for First Courier: Equation for the first courier: Total cost = $20\$20 + $1\$1 per pound. Let the weight of the package be ww pounds. Then, the cost equation is C=1w+20C = 1w + 20.
  2. Cost Equation for Second Courier: Equation for the second courier: Total cost = $8\$8 + $3\$3 per pound. Using the same variable ww for weight, the cost equation is C=3w+8C = 3w + 8.
  3. Set Equations Equal: Set the two equations equal to find the weight ww where the costs are the same: 1w+20=3w+81w + 20 = 3w + 8.
  4. Solve for Weight: Solve for ww: Subtract 1w1w from both sides to get 20=2w+820 = 2w + 8; then subtract 88 from both sides to get 12=2w12 = 2w.
  5. Find Weight: Divide both sides by 22 to find ww: w=122=6w = \frac{12}{2} = 6 pounds.
  6. Substitute to Find Cost: Substitute ww back into either courier's cost equation to find the cost: Using the first courier's equation, C=1(6)+20=6+20=26C = 1(6) + 20 = 6 + 20 = 26 dollars.

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