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Question
Answer the statistical measures and create a box and whiskers plot for the following set of data.

7,9,9,11,12,14,15,18
(Guided)
Min:
Q1:
Med:
Q3:
Max:
Create the box plot by dragging the lines:

Score: 0/3 0 / 3 \newlinePenalty: 11 off\newlineWatch Video\newlineShow Examp\newlineComplete: 71% 71 \% \newlineQuestion\newlineAnswer the statistical measures and create a box and whiskers plot for the following set of data.\newline7,9,9,11,12,14,15,18 7,9,9,11,12,14,15,18 \newline(Guided)\newlineMin:\newlineQ11:\newlineMed:\newlineQ33:\newlineMax:\newlineCreate the box plot by dragging the lines:

Full solution

Q. Score: 0/3 0 / 3 \newlinePenalty: 11 off\newlineWatch Video\newlineShow Examp\newlineComplete: 71% 71 \% \newlineQuestion\newlineAnswer the statistical measures and create a box and whiskers plot for the following set of data.\newline7,9,9,11,12,14,15,18 7,9,9,11,12,14,15,18 \newline(Guided)\newlineMin:\newlineQ11:\newlineMed:\newlineQ33:\newlineMax:\newlineCreate the box plot by dragging the lines:
  1. Find Minimum Value: First, we need to find the minimum value.\newlineMin = 77
  2. Calculate First Quartile: Next, we calculate the first quartile (Q11), which is the median of the lower half of the data. \newlineQ1=9+92Q1 = \frac{9 + 9}{2}\newlineQ1=9Q1 = 9
  3. Find Median: Now, let's find the median (Med\text{Med}) of the data set.Med=11+122\text{Med} = \frac{11 + 12}{2}Med=11.5\text{Med} = 11.5
  4. Determine Third Quartile: Then, we determine the third quartile (Q3Q_3), which is the median of the upper half of the data.\newlineQ3=(15+18)/2Q_3 = (15 + 18) / 2\newlineQ3=16.5Q_3 = 16.5
  5. Identify Maximum Value: Finally, we identify the maximum value. Max=18\text{Max} = 18
  6. Create Box Plot: Now, we would create the box plot, but since this is a text-based response, we can't actually drag lines to create it.

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