SB $-3$ $\newline$ Q $1$ . $1$ Identify their terms and their factors. $\newline$ $4a^{2}b^{2}-4a^{2}b^{2}c^{2}+c^{2}$ , $4a^{2}b^{2}-4a^{2}b^{2}c^{2}+c^{2}-4a^{2}b^{2}c^{2}-2\times 2\times 4\times \times \times x+b$ , $4a^{2}b^{2}\quad c^{2}=c \times c$ , $2\times 2\times a \times a \times b \times b \quad$

Full solution

Q. SB

-3

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1

1

Identify their terms and their factors.

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4a^{2}b^{2}-4a^{2}b^{2}c^{2}+c^{2}

4a^{2}b^{2}-4a^{2}b^{2}c^{2}+c^{2}-4a^{2}b^{2}c^{2}-2\times 2\times 4\times \times \times x+b

4a^{2}b^{2}\quad c^{2}=c \times c

2\times 2\times a \times a \times b \times b \quad

Identify terms in polynomial: First, let's look at the polynomial and identify each term. The polynomial is $4a^2b^2 - 4a^2b^2c^2 + c^2$ . So, we have three terms here: $4a^2b^2$ , $-4a^2b^2c^2$ , and $c^2$ .
Factor each term: Now, let's factor each term. The first term $4a^2b^2$ can be factored into $2 \times 2 \times a \times a \times b \times b$ . The second term $-4a^2b^2c^2$ can be factored into $-2 \times 2 \times a \times a \times b \times b \times c \times c$ . The third term $c^2$ is already a perfect square, so its factors are $c \times c$ .
Check for mistakes: Let's check if we made any mistakes. The first term looks good, the second term has the correct signs and factors, and the third term is also correct. No mistakes here.