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$A right rectangular prism has length 2(1)/(2) yd, width 1(1)/(2)yd, and height 3(1)/(2)yd. You use cubes with fractional edge length (1)/(2) each of the length, width, and height of the prism? Find the volume. How many cubes are there for each of the length, width, and height of the prism? The length has ◻ cubes, the width has ◻ cubes, and the height has ◻ cubes.$

A right rectangular prism has length $2 \frac{1}{2}$ yd, width $1 \frac{1}{2} \mathrm{yd}$ , and height $3 \frac{1}{2} \mathrm{yd}$ . You use cubes with fractional edge length $\frac{1}{2}$ each of the length, width, and height of the prism? Find the volume. $\newline$ How many cubes are there for each of the length, width, and height of the prism? $\newline$ The length has $\square$ cubes, the width has $\square$ cubes, and the height has $\square$ cubes.

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Math Problems

Grade 6

One-step inequalities: word problems

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Q. A right rectangular prism has length

2 \frac{1}{2}

yd, width

1 \frac{1}{2} \mathrm{yd}

, and height

3 \frac{1}{2} \mathrm{yd}

. You use cubes with fractional edge length

\frac{1}{2}

each of the length, width, and height of the prism? Find the volume.

\newline

How many cubes are there for each of the length, width, and height of the prism?

\newline

The length has

\square

cubes, the width has

\square

cubes, and the height has

\square

cubes.

Calculate Cube Fit Length: To find out how many $\frac{1}{2}$ yd cubes fit in the length of the prism, divide the length of the prism by the edge length of the cube. $2\frac{1}{2}$ yd $\div$ $\frac{1}{2}$ yd = $5$ yd.
Calculate Cube Fit Width: Now, let's do the same for the width. $\newline$ $\frac{1}{2}$ yd $\div$ $\frac{1}{2}$ yd = $3$ yd.
Calculate Cube Fit Height: Lastly, we'll find out how many cubes fit in the height. $\frac{3}{2} \, \text{yd} \div \frac{1}{2} \, \text{yd} = 7 \, \text{yd}.$
Correct Calculation Mistake: Oops, I made a mistake in the calculations. I should have kept the units consistent and not dropped them during the division. Let's correct that. $2(1)/(2) \, \text{yd} \div (1)/(2) \, \text{yd} = 5 \, \text{cubes}.$