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Samir works at a coffee shop on weekends. Every now and then, a customer will order a hot tea and ask Samir to surprise them with the flavor. The teas are categorized by flavor and caffeine level.\newlineThe probability that a tea is fruity is 0.20.2, the probability that it is caffeine-free is 0.40.4, and the probability that it is fruity and caffeine-free is 0.10.1.\newlineWhat is the probability that a randomly chosen tea is fruity or caffeine-free?\newlineWrite your answer as a whole number, decimal, or simplified fraction.

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Q. Samir works at a coffee shop on weekends. Every now and then, a customer will order a hot tea and ask Samir to surprise them with the flavor. The teas are categorized by flavor and caffeine level.\newlineThe probability that a tea is fruity is 0.20.2, the probability that it is caffeine-free is 0.40.4, and the probability that it is fruity and caffeine-free is 0.10.1.\newlineWhat is the probability that a randomly chosen tea is fruity or caffeine-free?\newlineWrite your answer as a whole number, decimal, or simplified fraction.
  1. Denote Events: Let's denote the events as follows:\newlineF: The tea is fruity.\newlineC: The tea is caffeine-free.\newlineWe are given the following probabilities:\newlineP(F)=0.2P(F) = 0.2\newlineP(C)=0.4P(C) = 0.4\newlineP(F and C)=0.1P(F \text{ and } C) = 0.1
  2. Use Addition Rule: We need to find the probability that a randomly chosen tea is fruity or caffeine-free. We can use the Addition Rule of Probability:\newlineP(F or C)=P(F)+P(C)P(F and C)P(F \text{ or } C) = P(F) + P(C) - P(F \text{ and } C)
  3. Substitute Values: Substitute the given values into the formula:\newlineP(F or C)=0.2+0.40.1P(F \text{ or } C) = 0.2 + 0.4 - 0.1
  4. Perform Calculation: Now, let's do the calculation:\newlineP(F or C)=0.5P(F \text{ or } C) = 0.5

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