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Saientist put an experiment to measure the gravitational force using two large spheres. In addition, both the spheres are 
1000.0kg, and their centres of mass are 
2000.0 m apart. Now, calculate the gravitat inal force between these two spheres?

Saientist put an experiment to measure the gravitational force using two large spheres. In addition, both the spheres are 1000.0 kg 1000.0 \mathrm{~kg} , and their centres of mass are 2000.0m 2000.0 m apart. Now, calculate the gravitat inal force between these two spheres?

Full solution

Q. Saientist put an experiment to measure the gravitational force using two large spheres. In addition, both the spheres are 1000.0 kg 1000.0 \mathrm{~kg} , and their centres of mass are 2000.0m 2000.0 m apart. Now, calculate the gravitat inal force between these two spheres?
  1. Calculate Gravitational Force: Step 11: Use Newton's Law of Universal Gravitation formula, F=G×(m1×m2)/r2F = G \times (m_1 \times m_2) / r^2, where GG is the gravitational constant (6.67430×1011 N(m2/kg2))(6.67430 \times 10^{-11} \text{ N(m}^2/\text{kg}^2)), m1m_1 and m2m_2 are the masses of the objects, and rr is the distance between their centers.\newlineCalculation: G=6.67430×1011 N(m2/kg2)G = 6.67430 \times 10^{-11} \text{ N(m}^2/\text{kg}^2), m1=1000.0 kgm_1 = 1000.0 \text{ kg}, m2=1000.0 kgm_2 = 1000.0 \text{ kg}, r=2000.0 mr = 2000.0 \text{ m}.\newlineGG00
  2. Perform Force Calculation: Step 22: Perform the calculations for the force.\newlineCalculation: F=(6.67430×1011)×(1000000)/(4000000)F = (6.67430 \times 10^{-11}) \times (1000000) / (4000000)\newlineF=(6.67430×1011)×(0.25)F = (6.67430 \times 10^{-11}) \times (0.25)\newlineF=1.668575×1011 NF = 1.668575 \times 10^{-11} \text{ N}

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