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S_(15) if 
a_(1) and 
a_(n)=-2a

S15 S_{15} if a1 a_{1} and an=2a a_{n}=-2 a

Full solution

Q. S15 S_{15} if a1 a_{1} and an=2a a_{n}=-2 a
  1. Find common difference: Find the common difference dd of the arithmetic sequence.an=a1+(n1)da_n = a_1 + (n - 1)d2a=a1+(151)d-2a = a_1 + (15 - 1)d2a=a1+14d-2a = a_1 + 14dd=2aa114d = \frac{-2a - a_1}{14}
  2. Calculate sum of first 1515 terms: Calculate the sum of the first 1515 terms S15S_{15} using the formula for the sum of an arithmetic sequence.\newlineS15=n2(a1+an)S_{15} = \frac{n}{2} \cdot (a_{1} + a_{n})\newlineS15=152(a1+(2a))S_{15} = \frac{15}{2} \cdot (a_{1} + (-2a))\newlineS15=152(a12a)S_{15} = \frac{15}{2} \cdot (a_{1} - 2a)
  3. Simplify expression for S15S_{15}: Simplify the expression for S15S_{15}.
    S15=152(a1+2a)S_{15} = \frac{15}{2} \cdot (a_{1} + 2a)
    S15=15a12152a2S_{15} = \frac{15a_{1}}{2} - \frac{15 \cdot 2a}{2}
    S15=15a1215aS_{15} = \frac{15a_{1}}{2} - 15a

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