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The cost of a certain number of pens is 
₹72. If the cost of each pen is decreased by then 8 more pens can be purchased for the same amount. How many pens can be purey for the same amount if the cost of each pen is increased by 
₹1.50 ?

rrect answer.\newlineThe cost of a certain number of pens is 72 ₹ 72 . If the cost of each pen is decreased by then 88 more pens can be purchased for the same amount. How many pens can be purey for the same amount if the cost of each pen is increased by 1.50 ₹ 1.50 ?

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Q. rrect answer.\newlineThe cost of a certain number of pens is 72 ₹ 72 . If the cost of each pen is decreased by then 88 more pens can be purchased for the same amount. How many pens can be purey for the same amount if the cost of each pen is increased by 1.50 ₹ 1.50 ?
  1. Define xx as original cost: Let xx be the original cost of each pen. Then the number of pens that can be bought for 72\text{₹}72 is 72x\frac{72}{x}.
  2. Calculate new cost: If the cost of each pen is decreased by ₹11, then the new cost of each pen is x1x - 1. So, 88 more pens can be bought, which means the new number of pens that can be bought for ₹7272 is 72/(x1)72/(x - 1).
  3. Formulate equation: According to the problem, the number of pens bought for 72\text{₹}72 at the original price is 88 less than the number of pens bought at the reduced price. So, we have the equation 72x+8=72x1\frac{72}{x} + 8 = \frac{72}{x - 1}.
  4. Clear denominators: Multiply both sides of the equation by x(x1)x(x - 1) to clear the denominators: x(x1)(72x+8)=x(x1)(72x1)x(x - 1)(\frac{72}{x} + 8) = x(x - 1)(\frac{72}{x - 1}).
  5. Simplify equation: Simplify the equation: 72(x1)+8x(x1)=72x72(x - 1) + 8x(x - 1) = 72x.
  6. Combine like terms: Distribute and combine like terms: 72x72+8x28x=72x72x - 72 + 8x^2 - 8x = 72x.
  7. Subtract 72x72x: Subtract 72x72x from both sides to get: 8x28x72=08x^2 - 8x - 72 = 0.
  8. Divide by 88: Divide the entire equation by 88 to simplify: x2x9=0x^2 - x - 9 = 0.

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