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root(3)(729)=

7293=\sqrt[3]{729} =

Full solution

Q. 7293=\sqrt[3]{729} =
  1. Identify the cube root: Identify the cube root of 729729.\newlineTo find the cube root of 729729, we need to find a number that, when multiplied by itself three times, gives 729729.
  2. Find the prime factors: Find the prime factors of 729729.\newlinePrime factors of 729729 are 3×3×3×3×3×33 \times 3 \times 3 \times 3 \times 3 \times 3, because 729729 is 33 raised to the power of 66 (363^6).
  3. Express 729729 as a cube: Express 729729 as a cube of a product of prime factors.\newline729729 can be written as (33)×(33)(3^3) \times (3^3), which is the same as 27×2727 \times 27.
  4. Simplify the cube root: Simplify the cube root of 729729 using the prime factorization.\newline7293=(33)×(33)3\sqrt[3]{729} = \sqrt[3]{(3^3) \times (3^3)}\newlineSince the cube root of (33)(3^3) is 33, we can simplify this to:\newline7293=3×3\sqrt[3]{729} = 3 \times 3
  5. Calculate the final answer: Calculate the final answer.\newline3×33 \times 3 equals 99, so the cube root of 729729 is 99.