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Let’s check out your problem:

root(3)(5x-2)=(1)/(5)(x^(3)+2)

5x−23=15(x3+2) \sqrt[3]{5 x-2}=\frac{1}{5}\left(x^{3}+2\right)

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Quadratic equation with complex rootsright chevron icon

Full solution

Q. 5x−23=15(x3+2) \sqrt[3]{5 x-2}=\frac{1}{5}\left(x^{3}+2\right)
  1. Isolate cube root: Isolate the cube root by multiplying both sides by 55. \newline5×5x−23=5×15(x3+2)5 \times \sqrt[3]{5x - 2} = 5 \times \frac{1}{5}(x^{3} + 2)\newline5×5x−23=x3+25 \times \sqrt[3]{5x - 2} = x^{3} + 2
  2. Cube both sides: Cube both sides to eliminate the cube root.\newline(5⋅5x−23)3=(x3+2)3(5 \cdot \sqrt[3]{5x - 2})^3 = (x^{3} + 2)^3\newline125(5x−2)=x9+6x6+12x3+8125(5x - 2) = x^{9} + 6x^{6} + 12x^{3} + 8

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