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root(3)(4^(x+1))=2sqrt(8^(x))

4x+13=28x \sqrt[3]{4^{x+1}}=2 \sqrt{8^{x}}

Full solution

Q. 4x+13=28x \sqrt[3]{4^{x+1}}=2 \sqrt{8^{x}}
  1. Convert to Exponential Form: Convert the cube root and square root to exponential form:\newline4x+13=(4x+1)13\sqrt[3]{4^{x+1}} = (4^{x+1})^{\frac{1}{3}}\newline28x=2(8x)122\sqrt{8^{x}} = 2\cdot(8^{x})^{\frac{1}{2}}
  2. Simplify Exponents: Simplify the exponents:\newline(4(x+1))13=4(x+1)3(4^{(x+1)})^{\frac{1}{3}} = 4^{\frac{(x+1)}{3}}\newline2(8x)12=2(23x)12=223x22\cdot(8^{x})^{\frac{1}{2}} = 2\cdot(2^{3x})^{\frac{1}{2}} = 2\cdot2^{\frac{3x}{2}}
  3. Set Equal: Set the expressions equal to each other:\newline4x+13=223x24^{\frac{x+1}{3}} = 2\cdot2^{\frac{3x}{2}}
  4. Express as 222^2: Express 44 as 222^2 and simplify:\newline(22)x+13=223x2(2^2)^{\frac{x+1}{3}} = 2\cdot2^{\frac{3x}{2}}\newline22x+13=21+3x22^{2\frac{x+1}{3}} = 2^{1+\frac{3x}{2}}
  5. Set Exponents Equal: Since the bases are the same, set the exponents equal to each other: 2(x+1)3=1+3x2\frac{2(x+1)}{3} = 1+\frac{3x}{2}
  6. Cross Multiply: Cross multiply to solve for xx:4(x+1)=3(1+3x2)4(x+1) = 3(1+\frac{3x}{2})4x+4=3+9x24x+4 = 3+\frac{9x}{2}
  7. Multiply by 22: Multiply everything by 22 to get rid of the fraction:\newline8x+8=6+9x8x+8 = 6+9x
  8. Subtract 8x8x: Subtract 8x8x from both sides:\newline8=6+x8 = 6+x

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