Resourcesdown chevron
Testimonials
Plans
Sign in
Sign up
Resourcesright arrow
Testimonials
Plans
Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

R(q)=-0.31(q-260)^(2)+9,500 A shoe manufacturer determines that its monthly revenue, R(q), in dollars, is given by the function, where q is the number of pairs of shoes sold each month. What is the maximum value of the company's monthly revenue in dollars?

R(q)=−0.31(q−260)2+9,500 R(q)=-0.31(q-260)^{2}+9,500 \newlineA shoe manufacturer determines that its monthly revenue, R(q) R(q) , in dollars, is given by the function, where q q is the number of pairs of shoes sold each month. What is the maximum value of the company's monthly revenue in dollars?

View step-by-step helpView step-by-step help
Homeright chevron icon
Math Problemsright chevron icon
Algebra 1right chevron icon
Solve quadratic equations: word problemsright chevron icon

Full solution

Q. R(q)=−0.31(q−260)2+9,500 R(q)=-0.31(q-260)^{2}+9,500 \newlineA shoe manufacturer determines that its monthly revenue, R(q) R(q) , in dollars, is given by the function, where q q is the number of pairs of shoes sold each month. What is the maximum value of the company's monthly revenue in dollars?
  1. Identify Function Type: Identify the type of function. The revenue function R(q)R(q) is a quadratic function in the form of R(q)=a(q−h)2+kR(q) = a(q - h)^2 + k, where (h,k)(h, k) is the vertex of the parabola.
  2. Determine Parabola Direction: Since the coefficient of (q−260)2(q - 260)^2 is negative (−0.31)(-0.31), the parabola opens downwards, which means the vertex is the maximum point.
  3. Find Vertex Coordinates: The vertex form of the parabola gives us the hh and kk values directly. Here, h=260h = 260 and k=9,500k = 9,500, which means the vertex is at (260,9500)(260, 9500).
  4. Calculate Maximum Revenue: The kk value of the vertex represents the maximum value of the company's monthly revenue. So, the maximum revenue is $9,500.

More problems from Solve quadratic equations: word problems

Question
Solve for v v .\newlinev2+8v+12=0 v^2+8v+12=0\newlineWrite each solution as an integer, proper fraction, or improper fraction in simplest form. If there are multiple solutions, separate them with commas.\newlinev= v=_____
Get tutor helpright-arrow

Posted 1 month ago

Question
Solve for u u .\newlineu2=9 u^2 = 9 \newlineWrite your answers as integers or as proper or improper fractions in simplest form.\newlineu= u = _____ or u= u = _____
Get tutor helpright-arrow

Posted 2 months ago

Question
Complete the square. Fill in the number that makes the polynomial a perfect-square quadratic.\newlinek2−20k+_____k^2 - 20k + \_\_\_\_\_
Get tutor helpright-arrow

Posted 2 months ago

Question
Solve by completing the square.\newlineu2−24u−23=0u^2 - 24u - 23 = 0\newlineWrite your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth.\newline`u` = ________ or `u` =______
Get tutor helpright-arrow

Posted 2 months ago

Question
Find the discriminant. \newline2q2−9q+8=02q^2 - 9q + 8 = 0\newline______
Get tutor helpright-arrow

Posted 2 months ago

Question
Solve the system of equations.\newliney=22x−38 y = 22x - 38 \newliney=x2+11x−14 y = x^2 + 11x - 14 \newlineWrite the coordinates in exact form. Simplify all fractions and radicals.\newline(_,_) (\_,\_) \newline(_,_) (\_,\_)
Get tutor helpright-arrow

Posted 1 month ago

Question
Solve for aa.\newline(a+5)(a+1)=0(a + 5)(a + 1) = 0\newlineWrite your answers as integers or as proper or improper fractions in simplest form.\newlinea=a = _____ or a=a = _____
Get tutor helpright-arrow

Posted 2 months ago

Question
Let p=x2−7 p=x^{2}-7 . Which equation is equivalent to (x2−7)2−4x2+28=5 (x^{2}-7)^{2}-4x^{2}+28=5 in terms of p p ? Choose 11 answer: \newline(A) p2−4p+23=0 p^{2}-4p+23=0 \newline(B) p2+4p−5=0 p^{2}+4p-5=0 \newline(C) p2−4p−5=0 p^{2}-4p-5=0 \newline(D) p2+4p+23=0 p^{2}+4p+23=0
Get tutor helpright-arrow

Posted 2 months ago

Question
Let m=2x+3m=2x+3. Which equation is equivalent to (2x+3)2−14x−21=−6(2x+3)^{2}-14x-21=-6 in terms of mm? Choose 11 answer: \newline(A) m2+7m+6=0m^{2}+7m+6=0 \newline(B) m2−7m−15=0m^{2}-7m-15=0 \newline(C) m2−7m+6=0m^{2}-7m+6=0 \newline(D) m2+7m−15=0m^{2}+7m-15=0
Get tutor helpright-arrow

Posted 2 months ago

Question
Let m=x2+3m=x^{2}+3. Which equation is equivalent to (x2+3)2+7x2+21=−10(x^{2}+3)^{2}+7x^{2}+21=-10 in terms of mm? Choose 11 answer:\newline(A) m2−7m+31=0m^{2}-7m+31=0\newline(B) m2+7m+31=0m^{2}+7m+31=0\newline(C) m2−7m+10=0m^{2}-7m+10=0\newline(D) m2+7m+10=0m^{2}+7m+10=0
Get tutor helpright-arrow

Posted 2 months ago

View all (42)