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quotion four different ways. Show ll work for creditl

x^(2)+2x!=-3quadx^(2)+2x-3=0
Graphing
You must plot accurate

quotion four different ways. Show ll work for creditl $\newline$ $x^{2}+2 x \neq-3 \quad x^{2}+2 x-3=0$ $\newline$ Graphing $\newline$ You must plot accurate

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Add and subtract integers: word problems

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Q. quotion four different ways. Show ll work for creditl

\newline

x^{2}+2 x \neq-3 \quad x^{2}+2 x-3=0

\newline

Graphing

\newline

You must plot accurate

Factoring: First method: Factoring. $\newline$ $x^2 + 2x - 3 = 0$ can be factored into $(x + 3)(x - 1) = 0$ .
Set equal and solve: Set each factor equal to zero: $x + 3 = 0$ or $x - 1 = 0$ .
Completing the square: Solve for $x$ : $x = -3$ or $x = 1$ .
Take square root and solve: Second method: Completing the square. $x^2 + 2x = 3$ . Add $(\frac{2}{2})^2 = 1$ to both sides to complete the square.
Quadratic formula: We get $x^2 + 2x + 1 = 4$ , which is $(x + 1)^2 = 4$ .
Calculate discriminant: Take the square root of both sides: $x + 1 = \pm 2$ .
Graphing: Solve for $x$ : $x = -1 \pm 2$ , which gives $x = 1$ or $x = -3$ .
Graphing: Solve for $x$ : $x = -1 \pm 2$ , which gives $x = 1$ or $x = -3$ .Third method: Quadratic formula. $x = [-2 \pm \sqrt{2^2 - 4(1)(-3)}]/(2\cdot1)$ .
Graphing: Solve for $x$ : $x = -1 \pm 2$ , which gives $x = 1$ or $x = -3$ .Third method: Quadratic formula. $x = [-2 \pm \sqrt{2^2 - 4(1)(-3)}]/(2\cdot1)$ .Calculate the discriminant: $\sqrt{4 + 12} = \sqrt{16}$ .
Graphing: Solve for $x$ : $x = -1 \pm 2$ , which gives $x = 1$ or $x = -3$ .Third method: Quadratic formula. $x = [-2 \pm \sqrt{2^2 - 4(1)(-3)}]/(2\cdot1)$ .Calculate the discriminant: $\sqrt{4 + 12} = \sqrt{16}$ .Solve for $x$ : $x = [-2 \pm 4]/2$ , which gives $x = 1$ or $x = -3$ .
Graphing: Solve for $x$ : $x = -1 \pm 2$ , which gives $x = 1$ or $x = -3$ .Third method: Quadratic formula. $x = [-2 \pm \sqrt{2^2 - 4(1)(-3)}]/(2\cdot1)$ .Calculate the discriminant: $\sqrt{4 + 12} = \sqrt{16}$ .Solve for $x$ : $x = [-2 \pm 4]/2$ , which gives $x = 1$ or $x = -3$ .Fourth method: Graphing. $\newline$ Plot the equation $x = -1 \pm 2$ $0$ and find the x-intercepts.
Graphing: Solve for $x$ : $x = -1 \pm 2$ , which gives $x = 1$ or $x = -3$ .Third method: Quadratic formula. $x = [-2 \pm \sqrt{2^2 - 4(1)(-3)}]/(2\cdot1)$ .Calculate the discriminant: $\sqrt{4 + 12} = \sqrt{16}$ .Solve for $x$ : $x = [-2 \pm 4]/2$ , which gives $x = 1$ or $x = -3$ .Fourth method: Graphing.Plot the equation $x = -1 \pm 2$ $0$ and find the x-intercepts.The x-intercepts are the solutions to the equation, which are $x = 1$ and $x = -3$ .

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