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Question
Watch Video
Show Examples
Find the equation of a line perpendicular to
2x-2y=2 that passes through the point
(-1,4).
Answer

y-4=-(x+1)

y+4=-(x-1)

y-4=x+1

y+4=x-1
Submit Answer

Question $\newline$ Watch Video $\newline$ Show Examples $\newline$ Find the equation of a line perpendicular to $2 x-2 y=2$ that passes through the point $(-1,4)$ . $\newline$ Answer $\newline$ $y-4=-(x+1)$ $\newline$ $y+4=-(x-1)$ $\newline$ $y-4=x+1$ $\newline$ $y+4=x-1$ $\newline$ Submit Answer

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Write linear functions: word problems

Full solution

Q. Question

\newline

Watch Video

\newline

Show Examples

\newline

Find the equation of a line perpendicular to

2 x-2 y=2

that passes through the point

(-1,4)

.

\newline

Answer

\newline

y-4=-(x+1)

\newline

y+4=-(x-1)

\newline

y-4=x+1

\newline

y+4=x-1

\newline

Submit Answer

Find Slope: First, we need to find the slope of the given line $2x - 2y = 2$ . To do this, we'll rewrite the equation in slope-intercept form, which is $y = mx + b$ , where $m$ is the slope.
Calculate Negative Reciprocal: So, we'll solve for $y$ in the equation $2x - 2y = 2$ . $2y = 2x - 2$ $y = x - 1$ Now we can see that the slope of the given line is $1$ .
Use Point-Slope Form: Since we want a line perpendicular to the given line, we need the negative reciprocal of the slope of the given line. The negative reciprocal of $1$ is $-1$ .
Plug in Values: Now we use the point-slope form of the equation of a line, which is $y - y_1 = m(x - x_1)$ , where $m$ is the slope and $(x_1, y_1)$ is the point the line passes through.
Simplify Equation: We plug in the slope $-1$ and the point $(-1, 4)$ into the point-slope form. $\newline$ $y - 4 = -1(x - (-1))$ $\newline$ $y - 4 = -1(x + 1)$
Simplify Equation: We plug in the slope $-1$ and the point $(-1, 4)$ into the point-slope form. $\newline$ $y - 4 = -1(x - (-1))$ $\newline$ $y - 4 = -1(x + 1)$ Now we simplify the equation. $\newline$ $y - 4 = -x - 1$

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\newline

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\newline

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