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Question
Find an angle in each quadrant with a common reference angle with 
165^(@), from 
0^(@) <= theta < 360^(@)
Answer Attempt 1 out of 2
Quadrant I: Quadrant II:
Quadrant III:
Quadrant IV:
Submit Answer

Question\newlineFind an angle in each quadrant with a common reference angle with 165 165^{\circ} , from 0θ<360 0^{\circ} \leq \theta<360^{\circ} \newlineAnswer Attempt 11 out of 22\newlineQuadrant I: Quadrant II:\newlineQuadrant III:\newlineQuadrant IV:\newlineSubmit Answer

Full solution

Q. Question\newlineFind an angle in each quadrant with a common reference angle with 165 165^{\circ} , from 0θ<360 0^{\circ} \leq \theta<360^{\circ} \newlineAnswer Attempt 11 out of 22\newlineQuadrant I: Quadrant II:\newlineQuadrant III:\newlineQuadrant IV:\newlineSubmit Answer
  1. Find Reference Angle: The reference angle is the acute angle that an angle makes with the x-axis. To find the reference angle for 165165 degrees, which is in Quadrant II, we subtract it from 180180 degrees because it's the closest x-axis angle for angles in Quadrant II.\newlineReference angle = 180180 degrees - 165165 degrees = 1515 degrees.
  2. Quadrant I Angle: For Quadrant I, the angle with the same reference angle would be its own measure since reference angles in Quadrant I are the angles themselves. Therefore, the angle in Quadrant I is 1515 degrees.
  3. Quadrant II Angle: For Quadrant II, the angle is 165165 degrees, which is given in the problem.
  4. Quadrant III Angle: For Quadrant III, we add 180180 degrees to the reference angle because angles in Quadrant III are 180180 degrees plus their reference angle.\newlineQuadrant III angle = 180180 degrees + 1515 degrees = 195195 degrees.
  5. Quadrant IV Angle: For Quadrant IV, we subtract the reference angle from 360360 degrees because angles in Quadrant IV are 360360 degrees minus their reference angle.\newlineQuadrant IV angle = 360360 degrees - 1515 degrees = 345345 degrees.

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