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Question Completion Status:
a) Sign of the leading coefficient
b) Vertex
c) Axis of symmetry
d) Intervals where fis increasing and where fis decreasing
f) Domain and range

Question Completion Status:\newlinea) Sign of the leading coefficient\newlineb) Vertex\newlinec) Axis of symmetry\newlined) Intervals where fis increasing and where fis decreasing\newlinef) Domain and range

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Q. Question Completion Status:\newlinea) Sign of the leading coefficient\newlineb) Vertex\newlinec) Axis of symmetry\newlined) Intervals where fis increasing and where fis decreasing\newlinef) Domain and range
  1. Leading Coefficient Sign: a) To find the sign of the leading coefficient, look at the coefficient of x2x^2 in the function f(x)=ax2+bx+cf(x) = ax^2 + bx + c.\newlineIf a>0a > 0, the parabola opens upwards and the leading coefficient is positive.\newlineIf a<0a < 0, the parabola opens downwards and the leading coefficient is negative.
  2. Vertex Calculation: b) The vertex of a parabola given by f(x)=ax2+bx+cf(x) = ax^2 + bx + c is found using the formula (b2a,f(b2a))(-\frac{b}{2a}, f(-\frac{b}{2a})). Calculate b2a-\frac{b}{2a} to find the xx-coordinate of the vertex. Then, substitute this value into the function to find the yy-coordinate.
  3. Axis of Symmetry: c) The axis of symmetry is a vertical line that passes through the vertex of the parabola.\newlineIt has the equation x=b2ax = -\frac{b}{2a}.
  4. Function Increasing/Decreasing: d) The function ff is increasing on the interval where x>b2ax > -\frac{b}{2a} and decreasing where x<b2ax < -\frac{b}{2a} if a>0a > 0. If a<0a < 0, then ff is increasing where x<b2ax < -\frac{b}{2a} and decreasing where x>b2ax > -\frac{b}{2a}.
  5. Domain and Range: f) The domain of any quadratic function is all real numbers, or (,)(-\infty, \infty). The range depends on the sign of the leading coefficient aa and the vertex. If a>0a > 0, the range is [f(b2a),)[f(-\frac{b}{2a}), \infty). If a<0a < 0, the range is (,f(b2a)](-\infty, f(-\frac{b}{2a})].

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