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Question 9, Instructor-
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Assume that the paired data came from a population that is normally distributed. Using a 0.05 significance level and 
d=x-y, find 
bar(d), and 
s_(d).





x
13
10
18
13
8
9
3
8



y
11
8
13
8
8
13
5
5





bar(d)=0.875 (Round to three decimal places as needed.)

s_(d)=0.2 (Round to three decimal places as needed.)

Question 99, Instructor-\newlinecreated question\newlinepoints\newlinePoints: 00 of 11\newlineSave\newlineAssume that the paired data came from a population that is normally distributed. Using a 00.0505 significance level and d=xy d=x-y , find dˉ \bar{d} , and sd s_{d} .\newline\begin{tabular}{lcccccccc}\newlinex \mathrm{x} & 1313 & 1010 & 1818 & 1313 & 88 & 99 & 33 & 88 \\\newliney \mathrm{y} & 1111 & 88 & 1313 & 88 & 88 & 1313 & 55 & 55\newline\end{tabular}\newlinedˉ=0.875 \bar{d}=0.875 (Round to three decimal places as needed.)\newlinesd=0.2 s_{d}=0.2 (Round to three decimal places as needed.)

Full solution

Q. Question 99, Instructor-\newlinecreated question\newlinepoints\newlinePoints: 00 of 11\newlineSave\newlineAssume that the paired data came from a population that is normally distributed. Using a 00.0505 significance level and d=xy d=x-y , find dˉ \bar{d} , and sd s_{d} .\newline\begin{tabular}{lcccccccc}\newlinex \mathrm{x} & 1313 & 1010 & 1818 & 1313 & 88 & 99 & 33 & 88 \\\newliney \mathrm{y} & 1111 & 88 & 1313 & 88 & 88 & 1313 & 55 & 55\newline\end{tabular}\newlinedˉ=0.875 \bar{d}=0.875 (Round to three decimal places as needed.)\newlinesd=0.2 s_{d}=0.2 (Round to three decimal places as needed.)
  1. Find Differences: First, let's find the differences d=xyd=x-y for each pair of data.
  2. Calculate Differences: The differences are: 1311=213-11=2, 108=210-8=2, 1813=518-13=5, 138=513-8=5, 88=08-8=0, 913=49-13=-4, 35=23-5=-2, 85=38-5=3.
  3. Calculate Mean: Now, let's calculate the mean of these differences dˉ\bar{d}. Add them up: 2+2+5+5+042+3=112+2+5+5+0-4-2+3=11.
  4. Calculate Mean: There are 88 differences, so dˉ=118=1.375\bar{d} = \frac{11}{8} = 1.375.

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