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Question 9/15
NEXT
BOOKMARK
REAGAN JURCA
(1)
00:47
9 Part A
(a) Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5 ?
(A)
(1)/(2)
(B)
(2)/(5)
(C)
(8)/(15)
(D)
(9)/(20)
(b)
Part B
In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is blue or green? Write your result as a simple decimal rounded to the thousandths place.

P(E)=

◻

Question $9$ / $15$ $\newline$ NEXT $\newline$ BOOKMARK $\newline$ REAGAN JURCA $\newline$ ( $1$ ) $00: 47$ $\newline$ $9$ Part A $\newline$ (a) Tickets numbered $1$ to $20$ are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of $3$ or $5$ ? $\newline$ (A) $\frac{1}{2}$ $\newline$ (B) $\frac{2}{5}$ $\newline$ (C) $\frac{8}{15}$ $\newline$ (D) $\frac{9}{20}$ $\newline$ (b) $\newline$ Part B $\newline$ In a box, there are $8$ red, $7$ blue and $6$ green balls. One ball is picked up randomly. What is the probability that it is blue or green? Write your result as a simple decimal rounded to the thousandths place. $\newline$ $P(\mathrm{E})=$ $\newline$ $\square$

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Probability of one event

Full solution

Q. Question

9

/

15

\newline

NEXT

\newline

BOOKMARK

\newline

REAGAN JURCA

\newline

(

1

)

00: 47

\newline

9

Part A

\newline

(a) Tickets numbered

1

to

20

are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of

3

or

5

?

\newline

(A)

\frac{1}{2}

\newline

(B)

\frac{2}{5}

\newline

(C)

\frac{8}{15}

\newline

(D)

\frac{9}{20}

\newline

(b)

\newline

Part B

\newline

In a box, there are

8

red,

7

blue and

6

green balls. One ball is picked up randomly. What is the probability that it is blue or green? Write your result as a simple decimal rounded to the thousandths place.

\newline

P(\mathrm{E})=

\newline

\square

Calculate Multiples: Question $9/15$ Part A: Calculate the multiples of $3$ and $5$ between $1$ and $20$ . $\newline$ Multiples of $3$ : $3$ , $6$ , $9$ , $12$ , $3$ $0$ , $3$ $1$ ( $6$ multiples) $\newline$ Multiples of $5$ : $5$ , $3$ $5$ , $3$ $0$ , $20$ ( $3$ $8$ multiples) $\newline$ Notice that $3$ $0$ is a common multiple of both $3$ and $5$ , so we must subtract it once to avoid double counting. $\newline$ Total distinct multiples: $5$ $2$
Calculate Probability: Divide the number of favorable outcomes by the total number of outcomes to find the probability. $\newline$ Probability = $\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$ $\newline$ Probability = $\frac{9}{20}$
Calculate Total Balls: Question $9/15$ Part B: Calculate the total number of balls. $\newline$ Total balls $=$ Red balls $+$ Blue balls $+$ Green balls $\newline$ Total balls $= 8 + 7 + 6$ $\newline$ Total balls $= 21$
Calculate Probability: Calculate the probability of picking a blue or green ball. $\newline$ Probability = $(\text{Blue balls} + \text{Green balls}) / \text{Total balls}$ $\newline$ Probability = $(7 + 6) / 21$ $\newline$ Probability = $13 / 21$
Convert to Decimal: Convert the fraction to a decimal rounded to the thousandths place. $\newline$ Probability as a decimal = $\frac{13}{21} \approx 0.619$

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\newline

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\newline

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\newline

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\newline

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\newline

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\newline

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