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Question 7 Find the area of the trapezoid shown below ◻

Question 77\newlineFind the area of the trapezoid shown below\newline□ \square

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Full solution

Q. Question 77\newlineFind the area of the trapezoid shown below\newline□ \square
  1. Identify formula: Identify the formula for the area of a trapezoid, which is A=(12)⋅(b1+b2)⋅hA = (\frac{1}{2}) \cdot (b_1 + b_2) \cdot h, where b1b_1 and b2b_2 are the lengths of the two bases and hh is the height.
  2. Plug in values: Plug in the given values for the bases and the height into the formula. Let's assume the bases are 8 cm8\,\text{cm} and 12 cm12\,\text{cm}, and the height is 5 cm5\,\text{cm}. So, A=12×(8+12)×5A = \frac{1}{2} \times (8 + 12) \times 5.
  3. Calculate sum: Calculate the sum of the bases: 8+12=208 + 12 = 20 cm.
  4. Multiply by height: Multiply the sum of the bases by the height: 20×5=100 cm220 \times 5 = 100 \, \text{cm}^2.
  5. Multiply by 11/22: Multiply by 12\frac{1}{2} to find the area: (12)×100=50 cm2\left(\frac{1}{2}\right) \times 100 = 50 \, \text{cm}^2. Oops, wait, that's not right, I multiplied wrong.

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