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Question 7 * 1 point Given that a=([2],[3]),|a|= sqrt()(13) 5 13 4

Question 77 *\newline11 point\newlineGiven that a=(23),∣a∣= a=\left(\begin{array}{l}2 \\ 3\end{array}\right),|a|= \newline(13) \sqrt{ }(13) \newline55\newline1313\newline44

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Q. Question 77 *\newline11 point\newlineGiven that a=(23),∣a∣= a=\left(\begin{array}{l}2 \\ 3\end{array}\right),|a|= \newline(13) \sqrt{ }(13) \newline55\newline1313\newline44
  1. Use Vector Magnitude Formula: First, we need to use the formula for the magnitude of a vector, which is ∣a∣=a12+a22|\mathbf{a}| = \sqrt{a_1^2 + a_2^2} where a1a_1 and a2a_2 are the components of vector a\mathbf{a}. So, we plug in the values from vector a=([2],[3])\mathbf{a} = ([2], [3]) into the formula. This gives us ∣a∣=22+32|\mathbf{a}| = \sqrt{2^2 + 3^2}.
  2. Plug in Values: Now, we calculate the squares of the components.\newlineThis gives us ∣a∣=4+9|a| = \sqrt{4 + 9}.
  3. Calculate Squares: Next, we add the squares together.\newlineThis gives us ∣a∣=13\lvert a \rvert = \sqrt{13}.
  4. Add Squares: So, the magnitude of vector aa is 13\sqrt{13}, which is one of the options given.

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