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QUESTION 6
With reference to the Figure: What is the rate of acceleration of the object between the 15 and 20 second marks ( 15 - 20 seconds)? Note: Please express any deceleration answers by using a negative
(-) symbol in front of your numerical answer. Note 1 : The units are not required to be included in this instance. 0
qquad

QUESTION $6$ $\newline$ With reference to the Figure: What is the rate of acceleration of the object between the $15$ and $20$ second marks ( $15$ - $20$ seconds)? Note: Please express any deceleration answers by using a negative $(-)$ symbol in front of your numerical answer. Note $1$ : The units are not required to be included in this instance. $0$ $\qquad$

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Relate position, velocity, speed, and acceleration using derivatives

Full solution

Q. QUESTION

6

\newline

With reference to the Figure: What is the rate of acceleration of the object between the

15

and

20

second marks (

15

-

20

seconds)? Note: Please express any deceleration answers by using a negative

(-)

symbol in front of your numerical answer. Note

1

: The units are not required to be included in this instance.

0

\qquad

Find Change in Velocity: First, we need to find the change in velocity between $15$ and $20$ seconds.
Calculate Time Interval: We look at the graph and see the velocity at $15$ seconds and at $20$ seconds.
Calculate Acceleration: Let's say the velocity at $15$ seconds is $30\,\text{m/s}$ and at $20$ seconds it's $50\,\text{m/s}$ . So, the change in velocity is $50\,\text{m/s} - 30\,\text{m/s} = 20\,\text{m/s}$ .
Calculate Acceleration: Let's say the velocity at $15$ seconds is $30 \, \text{m/s}$ and at $20$ seconds it's $50 \, \text{m/s}$ . So, the change in velocity is $50 \, \text{m/s} - 30 \, \text{m/s} = 20 \, \text{m/s}$ .Now, we calculate the time interval, which is $20$ seconds - $15$ seconds = $5$ seconds.
Calculate Acceleration: Let's say the velocity at $15$ seconds is $30\,\text{m/s}$ and at $20$ seconds it's $50\,\text{m/s}$ . So, the change in velocity is $50\,\text{m/s} - 30\,\text{m/s} = 20\,\text{m/s}$ .Now, we calculate the time interval, which is $20$ seconds - $15$ seconds = $5$ seconds.To find the acceleration, we divide the change in velocity by the time interval. So, acceleration = $\frac{20\,\text{m/s}}{5\,\text{s}}$ .
Calculate Acceleration: Let's say the velocity at $15$ seconds is $30\,\text{m/s}$ and at $20$ seconds it's $50\,\text{m/s}$ . So, the change in velocity is $50\,\text{m/s} - 30\,\text{m/s} = 20\,\text{m/s}$ .Now, we calculate the time interval, which is $20$ seconds - $15$ seconds = $5$ seconds.To find the acceleration, we divide the change in velocity by the time interval. So, acceleration = $20\,\text{m/s} \div 5\,\text{s}$ .Doing the division gives us an acceleration of $4\,\text{m/s}^2$ .

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