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Question 5

1 point
The point 
Q(4,-5) has been translated from 
P(2,-3). What is the translation as a vector?


([-2],[2])quad([2],[2])
A
B

([-2],[-2])quad([2],[-2])

C
D

Question 55\newline* 11 point\newlineThe point Q(4,5) Q(4,-5) has been translated from P(2,3) P(2,-3) . What is the translation as a vector?\newline(22)(22) \left(\begin{array}{c} -2 \\ 2 \end{array}\right) \quad\left(\begin{array}{l} 2 \\ 2 \end{array}\right) \newlineA\newlineB\newline(22)(22) \left(\begin{array}{l} -2 \\ -2 \end{array}\right) \quad\left(\begin{array}{c} 2 \\ -2 \end{array}\right) \newlineC \mathrm{C} \newlineD

Full solution

Q. Question 55\newline* 11 point\newlineThe point Q(4,5) Q(4,-5) has been translated from P(2,3) P(2,-3) . What is the translation as a vector?\newline(22)(22) \left(\begin{array}{c} -2 \\ 2 \end{array}\right) \quad\left(\begin{array}{l} 2 \\ 2 \end{array}\right) \newlineA\newlineB\newline(22)(22) \left(\begin{array}{l} -2 \\ -2 \end{array}\right) \quad\left(\begin{array}{c} 2 \\ -2 \end{array}\right) \newlineC \mathrm{C} \newlineD
  1. Subtract coordinates for xx: To find the translation vector, we subtract the coordinates of the original point PP from the coordinates of the translated point QQ.
  2. Subtract coordinates for y: So, we do (42)(4 - 2) for the xx-coordinates and (5(3))(-5 - (-3)) for the yy-coordinates.
  3. Calculate x-coordinate: This gives us (42)=2(4 - 2) = 2 for the x-coordinate and (5+3)=2(-5 + 3) = -2 for the y-coordinate of the translation vector.
  4. Calculate y-coordinate: Therefore, the translation vector is ([2][2], [2][-2]).

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