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Question 3
What is the solution to the equati

log_(6)4x^(2)-log_(6)x=2
A.

Question 33\newlineWhat is the solution to the equati\newlinelog64x2log6x=2 \log _{6} 4 x^{2}-\log _{6} x=2 \newlineA.

Full solution

Q. Question 33\newlineWhat is the solution to the equati\newlinelog64x2log6x=2 \log _{6} 4 x^{2}-\log _{6} x=2 \newlineA.
  1. Simplify Logarithm: Now simplify the expression inside the logarithm. log6(4x)=2\log_{6}(4x) = 2
  2. Rewrite in Exponential Form: To solve for xx, we need to rewrite the equation in exponential form.62=4x6^2 = 4x
  3. Calculate Exponential Value: Calculate 626^2. 36=4x36 = 4x
  4. Divide to Solve for x: Now, divide both sides by 44 to solve for x.\newlinex=364x = \frac{36}{4}
  5. Final Solution: Finally, do the division. x=9x = 9

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