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Quadratic Formu.

Solve the following equa
(a) 
2x^(2)+x-3=0

Quadratic Formu.\newline11. Solve the following equa\newline(a) 2x2+x3=0 2 x^{2}+x-3=0

Full solution

Q. Quadratic Formu.\newline11. Solve the following equa\newline(a) 2x2+x3=0 2 x^{2}+x-3=0
  1. Identify coefficients: Identify coefficients aa, bb, and cc in the quadratic equation 2x2+x3=02x^2 + x - 3 = 0.\newlinea=2a = 2, b=1b = 1, c=3c = -3.
  2. Use quadratic formula: Use the quadratic formula x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}. Substitute a=2a = 2, b=1b = 1, c=3c = -3 into the formula.
  3. Calculate discriminant: Calculate the discriminant b24acb^2 - 4ac.\newlineDiscriminant = 124(2)(3)=1+24=251^2 - 4(2)(-3) = 1 + 24 = 25.
  4. Calculate square root: Calculate the square root of the discriminant 25\sqrt{25}.\newlineSquare root = 25=5\sqrt{25} = 5.
  5. Substitute discriminant: Substitute the discriminant into the quadratic formula.\newlinex=1±522x = \frac{{-1 \pm \sqrt{5}}}{{2 \cdot 2}}.
  6. Simplify expression: Simplify the expression to find the two roots.\newlinex=1+54x = \frac{{-1 + 5}}{{4}} and x=154x = \frac{{-1 - 5}}{{4}}.\newlinex=44x = \frac{{4}}{{4}} and x=64x = \frac{{-6}}{{4}}.\newlinex=1x = 1 and x=1.5x = -1.5.

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