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qquad 33. Given: m/_IFG=128^(@) mIHF^(⏜)= qquad 2)^(@), find mDH^(⏜).

\qquad 3333. Given: m∠IFG=128∘ m \angle I F G=128^{\circ} \newline m \overparen{I H F}= \qquad \newline2)∘ 2)^{\circ} , find m \overparen{D H} .

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Q. \qquad 3333. Given: m∠IFG=128∘ m \angle I F G=128^{\circ} \newline m \overparen{I H F}= \qquad \newline2)∘ 2)^{\circ} , find m \overparen{D H} .
  1. Identify Relationship: Identify the relationship between the angles in the problem.\newlineSince m∠IFG=128∘m\angle IFG = 128^\circ and mIHF⌢=2∘m\overset{\frown}{IHF} = 2^\circ, we know that mDH⌢m\overset{\frown}{DH} is the difference between these two angles because the arc IHFIHF is part of the larger arc IFGIFG.
  2. Calculate Angle DH: Calculate the measure of angle DH.\newlinem∠DH=m∠IFG−m∠IHF=128∘−2∘=126∘.m\angle DH = m\angle IFG - m\angle IHF = 128^\circ - 2^\circ = 126^\circ.

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