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q6 [5 marks] Jack and Abdul had some stickers. If Jack gave Abdul 25 sitckers, they would have an equal number of stickers. If Abdul gave Jack 47 stickers, Jack would have 4 times as many stickers as Abdul. Jack has how many stickers? Abdul has how many stickers? Remarks 2P-50 {:[4v-188=2p-50],[4u-2p=188-50],[4u-2p=138]:} 4u-188

q66 [55 marks]\newlineJack and Abdul had some stickers. If Jack gave Abdul 2525 sitckers, they would have an equal number of stickers. If Abdul gave Jack 4747 stickers, Jack would have 44 times as many stickers as Abdul. Jack has how many stickers? Abdul has how many stickers?\newlineRemarks\newline2P−50 2 P-50 \newline4v−188=2p−504u−2p=188−504u−2p=138 \begin{array}{l} 4 v-188=2 p-50 \\ 4 u-2 p=188-50 \\ 4 u-2 p=138 \end{array} \newline4u−188 4 u-188

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Q. q66 [55 marks]\newlineJack and Abdul had some stickers. If Jack gave Abdul 2525 sitckers, they would have an equal number of stickers. If Abdul gave Jack 4747 stickers, Jack would have 44 times as many stickers as Abdul. Jack has how many stickers? Abdul has how many stickers?\newlineRemarks\newline2P−50 2 P-50 \newline4v−188=2p−504u−2p=188−504u−2p=138 \begin{array}{l} 4 v-188=2 p-50 \\ 4 u-2 p=188-50 \\ 4 u-2 p=138 \end{array} \newline4u−188 4 u-188
  1. Set Up Equations: Let's call the number of stickers Jack has JJ and the number of stickers Abdul has AA. If Jack gave Abdul 2525 stickers, they would have an equal number of stickers. So, J−25=A+25J - 25 = A + 25.
  2. Solve for JJ: If Abdul gave Jack 4747 stickers, Jack would have 44 times as many stickers as Abdul. So, J+47=4×(A−47)J + 47 = 4 \times (A - 47).
  3. Substitute JJ into Second Equation: Now we have two equations:\newline11) J−25=A+25J - 25 = A + 25\newline22) J+47=4×(A−47)J + 47 = 4 \times (A - 47)\newlineLet's solve the first equation for JJ: J=A+25+25J = A + 25 + 25, which simplifies to J=A+50J = A + 50.
  4. Solve for AA: Substitute J=A+50J = A + 50 into the second equation: (A+50)+47=4×(A−47)(A + 50) + 47 = 4 \times (A - 47). This simplifies to A+97=4A−188A + 97 = 4A - 188.
  5. Find A: Now, let's solve for AA: 97+188=4A−A97 + 188 = 4A - A, which simplifies to 285=3A285 = 3A.
  6. Find J: Divide both sides by 33 to find A: A=2853A = \frac{285}{3}, which simplifies to A=95A = 95.
  7. Find J: Divide both sides by 33 to find A: A=2853A = \frac{285}{3}, which simplifies to A=95A = 95.Now that we have AA, we can find JJ using the equation J=A+50J = A + 50: J=95+50J = 95 + 50, which simplifies to J=145J = 145.

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