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In a stationery shop cost of 3 books 2 pens and 2 pencils all together is Rs. 129. Cost of 1 book 2 pens and 2 pencils together is Rs.79. And cost of 1 book and 1 pencil together is Rs.37. If Ajinkya buys 4 books, 2 pencils and 3 pens. How much will he pay to the shopkeeper?
(A) Rs 31
(B) Rs 150
(C) Rs 189
(D) Rs 169

In a stationery shop cost of 33 books 22 pens and 22 pencils all together is Rs. 129129. Cost of 11 book 22 pens and 22 pencils together is Rs.7979. And cost of 11 book and 11 pencil together is Rs.3737. If Ajinkya buys 44 books, 22 pencils and 33 pens. How much will he pay to the shopkeeper?\newline(A) Rs 3131\newline(B) Rs 150150\newline(C) Rs 189189\newline(D) Rs 169169

Full solution

Q. In a stationery shop cost of 33 books 22 pens and 22 pencils all together is Rs. 129129. Cost of 11 book 22 pens and 22 pencils together is Rs.7979. And cost of 11 book and 11 pencil together is Rs.3737. If Ajinkya buys 44 books, 22 pencils and 33 pens. How much will he pay to the shopkeeper?\newline(A) Rs 3131\newline(B) Rs 150150\newline(C) Rs 189189\newline(D) Rs 169169
  1. Equations Setup: Let's denote the cost of one book as BB, the cost of one pen as PP, and the cost of one pencil as CC. We are given three equations based on the information provided:\newline11. For 33 books, 22 pens, and 22 pencils, the cost is Rs. 129129.\newline22. For 11 book, 22 pens, and 22 pencils, the cost is Rs. PP00.\newline33. For 11 book and 11 pencil, the cost is Rs. PP33.\newlineWe can write these equations as:\newlinePP44 ...(11)\newlinePP66 ...(22)\newlinePP88 ...(33)\newlineNow, we will solve these equations to find the values of BB, PP, and CC.
  2. Calculate Cost of Book: First, we will subtract equation (22) from equation (11) to find the cost of 22 books:\newline(3B+2P+2C)(B+2P+2C)=12979(3B + 2P + 2C) - (B + 2P + 2C) = 129 - 79\newline2B=502B = 50\newlineB=25B = 25\newlineSo, the cost of one book is Rs. 2525.
  3. Calculate Cost of Pencil: Next, we will substitute the value of BB into equation (33) to find the cost of one pencil:\newlineB+C=37B + C = 37\newline25+C=3725 + C = 37\newlineC=3725C = 37 - 25\newlineC=12C = 12\newlineSo, the cost of one pencil is Rs. 1212.
  4. Calculate Cost of Pen: Now, we will substitute the values of BB and CC into equation (2)(2) to find the cost of two pens:\newlineB+2P+2C=79B + 2P + 2C = 79\newline25+2P+2(12)=7925 + 2P + 2(12) = 79\newline25+2P+24=7925 + 2P + 24 = 79\newline2P=7925242P = 79 - 25 - 24\newline2P=302P = 30\newlineP=15P = 15\newlineSo, the cost of one pen is Rs. 1515.
  5. Total Cost Calculation: Finally, we will calculate the total cost for Ajinkya, who buys 44 books, 22 pencils, and 33 pens:\newlineTotal cost = 4B+2C+3P4B + 2C + 3P\newlineTotal cost = 4(25)+2(12)+3(15)4(25) + 2(12) + 3(15)\newlineTotal cost = 100+24+45100 + 24 + 45\newlineTotal cost = 169169\newlineSo, Ajinkya will pay Rs. 169169 to the shopkeeper.

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